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C string替换字符串

string.replace(str,"@@\","\\")就可以了 字符替换表 = { ["\"] = "\\"; ["'"] = ""; ["N"] = "n"; } str = string.replace( "替换'这里的\N",".|:", 字符替换表 ) io.open(); io.print( str )

不是可以用Replace么 CString a = "asdfghjkllkjhgfdsa"; CString b = "abcde"; a.Replace("asd",b); 这样就把a中的前三个字母位置替换成了abcde,此刻a为abcdefghjkllkjhgfdsa

string ori = "his name is Tom";string fnd = "Tom";string rep = "Jack";ori=ori.replace(ori.find(fnd), fnd.length(), rep); cout

一个个查找呗, 找\, 改成/ , 只要注意"\"是特殊字符, 需要转义, 连续打两个\\即可., 如下: for (i = 0; buf[i] != 0; i++) { if (buf[i] == '\\') buf[i] = '/'; }

String对象有Replace方法可以替换字符

#include #include #include // 将strRes中的t替换为s,替换成功返回1,否则返回0。int StrReplace(char strRes[],char from[], char to[]) {int i,flag = 0;char *p,*q,*ts;for(i = 0; strRes[i]; ++i) {if(strRes[i] == from[0]) {p = strRes ...

//#include "stdafx.h"//If the vc++6.0, with this line.#include "stdio.h"#include "string.h"int main(void){ char s[300],s1[50],s2[60],tmp[300]; int ls1,ls2,i,j; printf("Input string s,s1,s2...\n"); scanf("%s%s%s",s,s1,s2); ls1=s...

1. #include #include using namespace std; int main() { string str("abcdefg"); string::iterator it; for (it =str.begin(); it != str.end(); ++it) { if ( *it == 'c') { str.erase(it); } } cout

#include "stdafx.h"#include #include void replaceChar(char *string, char oldChar, char newChar){ int len = strlen(string); int i; for (i = 0; i < len; i++){ if (string[i] == oldChar){ string[i] = newChar; } }}int main(){ char s...

#include using namespace std;int ary_delete( int item, int* ary, int size_a ) {for ( int i=item; i

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